What are the solutions to the equation x^2-11x-126=0 ?

The solutions to the equation x^2-11x-126=0 are x=18,x=-7

Find the zeros of x^2-11x-126=0

The zeros of x^2-11x-126=0 are x=18,x=-7

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x^{2} - 11 x - 126 = 0

x = 18, x = - 7

Solution steps

x^{2} - 11 x - 126 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 126 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 126) = 25

x_{1, 2} = \frac{- ( - 11 ) \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 25}{2 \cdot 1}

x = \frac{- ( - 11 ) + 25}{2 \cdot 1} : 18

x = \frac{- ( - 11 ) - 25}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 18, x = - 7

- 2 x^{2} - x + 10 = 0

850000 = 0.638 x^{2} + 6.671 x + 627.619

(\frac{1 + 3 y}{2})^{2} + 2 y^{2} = 8

10 x^{2} + 11 x + 3 = 0

x, (z - 4)^{2} = 4 x^{2}

What are the solutions to the equation x^2-11x-126=0 ?
The solutions to the equation x^2-11x-126=0 are x=18,x=-7
Find the zeros of x^2-11x-126=0
The zeros of x^2-11x-126=0 are x=18,x=-7