What are the solutions to the equation -2x^2-x+10=0 ?

The solutions to the equation -2x^2-x+10=0 are x=-5/2 ,x=2

Find the zeros of -2x^2-x+10=0

The zeros of -2x^2-x+10=0 are x=-5/2 ,x=2

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- 2 x^{2} - x + 10 = 0

x = - \frac{5}{2}, x = 2

Decimal Notation

x = - 2.5, x = 2

Solution steps

- 2 x^{2} - x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 10 = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 9}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 9}{2 ( - 2 )} : - \frac{5}{2}

x = \frac{- ( - 1 ) - 9}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = 2

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(\frac{1 + 3 y}{2})^{2} + 2 y^{2} = 8

10 x^{2} + 11 x + 3 = 0

x, (z - 4)^{2} = 4 x^{2}

2 x^{2} + 7 x - 15 = 0

What are the solutions to the equation -2x^2-x+10=0 ?
The solutions to the equation -2x^2-x+10=0 are x=-5/2 ,x=2
Find the zeros of -2x^2-x+10=0
The zeros of -2x^2-x+10=0 are x=-5/2 ,x=2