What are the solutions to the equation completesquare 2x^2+7x-15=0 ?

The solutions to the equation completesquare 2x^2+7x-15=0 are x= 3/2 ,x=-5

Find the zeros of completesquare 2x^2+7x-15=0

The zeros of completesquare 2x^2+7x-15=0 are x= 3/2 ,x=-5

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2 x^{2} + 7 x - 15 = 0

x = \frac{3}{2}, x = - 5

Decimal Notation

x = 1.5, x = - 5

Solution steps

2 x^{2} + 7 x - 15 = 0

Move

15

to the right side

2 x^{2} + 7 x = 15

Divide both sides by

2

\frac{2 x ^{2} + 7 x}{2} = \frac{15}{2}

x^{2} + \frac{7 x}{2} = \frac{15}{2}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{7}{4})^{2} = \frac{169}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{7}{4} = \frac{169}{16} : x = \frac{3}{2}

Solve

x + \frac{7}{4} = - \frac{169}{16} : x = - 5

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 5

2 (x^{2} - 1) = x^{2} + 7

2 = x - 2 (x + 4)^{2}

2 x (2 x + 10) = - 25

3 x^{2} - 5 = - 4 x

2 x^{2} + 7 x + 12 = 0

What are the solutions to the equation completesquare 2x^2+7x-15=0 ?
The solutions to the equation completesquare 2x^2+7x-15=0 are x= 3/2 ,x=-5
Find the zeros of completesquare 2x^2+7x-15=0
The zeros of completesquare 2x^2+7x-15=0 are x= 3/2 ,x=-5