What are the solutions to the equation completesquare 2x^2+5x-1=0 ?

The solutions to the equation completesquare 2x^2+5x-1=0 are x=(sqrt(33)-5)/4 ,x=(-sqrt(33)-5)/4

Find the zeros of completesquare 2x^2+5x-1=0

The zeros of completesquare 2x^2+5x-1=0 are x=(sqrt(33)-5)/4 ,x=(-sqrt(33)-5)/4

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2 x^{2} + 5 x - 1 = 0

x = \frac{33 - 5}{4}, x = \frac{- 33 - 5}{4}

Decimal Notation

x = 0.18614 \dots, x = - 2.68614 \dots

Solution steps

2 x^{2} + 5 x - 1 = 0

Move

1

to the right side

2 x^{2} + 5 x = 1

Divide both sides by

2

\frac{2 x ^{2} + 5 x}{2} = \frac{1}{2}

x^{2} + \frac{5 x}{2} = \frac{1}{2}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{4})^{2} = \frac{33}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{4} = \frac{33}{16} : x = \frac{33 - 5}{4}

Solve

x + \frac{5}{4} = - \frac{33}{16} : x = \frac{- 33 - 5}{4}

The solutions to the quadratic equation are:

x = \frac{33 - 5}{4}, x = \frac{- 33 - 5}{4}

x^{2} - 4 x + 3 x = 0

31 x^{2} - 74 x - 57 = 0

\frac{n ( n - 3 )}{2} = 54

12 x^{2} + x - 35 = 0

u^{2} + 7 u + 6 = 0

What are the solutions to the equation completesquare 2x^2+5x-1=0 ?
The solutions to the equation completesquare 2x^2+5x-1=0 are x=(sqrt(33)-5)/4 ,x=(-sqrt(33)-5)/4
Find the zeros of completesquare 2x^2+5x-1=0
The zeros of completesquare 2x^2+5x-1=0 are x=(sqrt(33)-5)/4 ,x=(-sqrt(33)-5)/4