What are the solutions to the equation 12x^2-2028x+62370=0 ?

The solutions to the equation 12x^2-2028x+62370=0 are x=(169+sqrt(7771))/2 ,x=(169-sqrt(7771))/2

Find the zeros of 12x^2-2028x+62370=0

The zeros of 12x^2-2028x+62370=0 are x=(169+sqrt(7771))/2 ,x=(169-sqrt(7771))/2

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12 x^{2} - 2028 x + 62370 = 0

x = \frac{169 + 7771}{2}, x = \frac{169 - 7771}{2}

Decimal Notation

x = 128.57663 \dots, x = 40.42336 \dots

Solution steps

12 x^{2} - 2028 x + 62370 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2028 ) \pm ( - 2028 ) ^{2} - 4 \cdot 12 \cdot 62370}{2 \cdot 12}

(- 2028)^{2} - 4 \cdot 12 \cdot 62370 = 127771

x_{1, 2} = \frac{- ( - 2028 ) \pm 12 7771}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 2028 ) + 12 7771}{2 \cdot 12}, x_{2} = \frac{- ( - 2028 ) - 12 7771}{2 \cdot 12}

x = \frac{- ( - 2028 ) + 12 7771}{2 \cdot 12} : \frac{169 + 7771}{2}

x = \frac{- ( - 2028 ) - 12 7771}{2 \cdot 12} : \frac{169 - 7771}{2}

The solutions to the quadratic equation are:

x = \frac{169 + 7771}{2}, x = \frac{169 - 7771}{2}

2 5^{2} = 7^{2} + b^{2}

2 x^{2} - 2 x + 1

- 26 = - x^{2} - 1

9 (x^{2} + 1) = 34

\frac{x ^{2}}{2} = 7 x

What are the solutions to the equation 12x^2-2028x+62370=0 ?
The solutions to the equation 12x^2-2028x+62370=0 are x=(169+sqrt(7771))/2 ,x=(169-sqrt(7771))/2
Find the zeros of 12x^2-2028x+62370=0
The zeros of 12x^2-2028x+62370=0 are x=(169+sqrt(7771))/2 ,x=(169-sqrt(7771))/2