What are the solutions to the equation x^2-16x-64=0 ?

The solutions to the equation x^2-16x-64=0 are x=8(1+sqrt(2)),x=8(1-sqrt(2))

Find the zeros of x^2-16x-64=0

The zeros of x^2-16x-64=0 are x=8(1+sqrt(2)),x=8(1-sqrt(2))

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x^{2} - 16 x - 64 = 0

x = 8 (1 + 2), x = 8 (1 - 2)

Decimal Notation

x = 19.31370 \dots, x = - 3.31370 \dots

Solution steps

x^{2} - 16 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 64) = 162

x_{1, 2} = \frac{- ( - 16 ) \pm 16 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16 2}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 16 2}{2 \cdot 1}

x = \frac{- ( - 16 ) + 16 2}{2 \cdot 1} : 8 (1 + 2)

x = \frac{- ( - 16 ) - 16 2}{2 \cdot 1} : 8 (1 - 2)

The solutions to the quadratic equation are:

x = 8 (1 + 2), x = 8 (1 - 2)

9 x^{2} + 15 x + 6 = 0

4 x^{2} - 5 x + 5 = 0

2 x^{2} - x - 12 = 0

- 3 x^{2} + 15 x - 12 = 0

2 x^{2} - 6 x = - 9

What are the solutions to the equation x^2-16x-64=0 ?
The solutions to the equation x^2-16x-64=0 are x=8(1+sqrt(2)),x=8(1-sqrt(2))
Find the zeros of x^2-16x-64=0
The zeros of x^2-16x-64=0 are x=8(1+sqrt(2)),x=8(1-sqrt(2))