What are the solutions to the equation solvefor x,f(x+h)=(x+h)^2 ?

The solutions to the equation solvefor x,f(x+h)=(x+h)^2 are x=-h,x=f-h

Find the zeros of solvefor x,f(x+h)=(x+h)^2

The zeros of solvefor x,f(x+h)=(x+h)^2 are x=-h,x=f-h

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solve for

x, f (x + h) = (x + h)^{2}

x = - h, x = f - h

Solution steps

f (x + h) = (x + h)^{2}

Switch sides

(x + h)^{2} = f (x + h)

Move

f (x + h)

to the left side

(x + h)^{2} - f (x + h) = 0

Factor

(x + h)^{2} - f (x + h) : (x + h) (x - f + h)

(x + h) (x - f + h) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + h = 0 or x - f + h = 0

Solve

x + h = 0 : x = - h

Solve

x - f + h = 0 : x = f - h

The solutions to the quadratic equation are:

x = - h, x = f - h

a, a^{2} + b^{2} + c^{2} + (a + b + c)^{2} = 202 2^{2}

X^{2} + 8 X + 16 = 0

x^{2} + 4 x + \frac{1}{2} = 0

x, z = 4 x^{2} + y^{2} + 1

\frac{1}{8} (5 r)^{2} π - π (3 r)^{2} \frac{1}{8} = \frac{81}{2} π

What are the solutions to the equation solvefor x,f(x+h)=(x+h)^2 ?
The solutions to the equation solvefor x,f(x+h)=(x+h)^2 are x=-h,x=f-h
Find the zeros of solvefor x,f(x+h)=(x+h)^2
The zeros of solvefor x,f(x+h)=(x+h)^2 are x=-h,x=f-h