What are the solutions to the equation -3s^2-30s-50=0 ?

The solutions to the equation -3s^2-30s-50=0 are s=-(5(3+sqrt(3)))/3 ,s=-(5(3-sqrt(3)))/3

Find the zeros of -3s^2-30s-50=0

The zeros of -3s^2-30s-50=0 are s=-(5(3+sqrt(3)))/3 ,s=-(5(3-sqrt(3)))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 s^{2} - 30 s - 50 = 0

s = - \frac{5 ( 3 + 3 )}{3}, s = - \frac{5 ( 3 - 3 )}{3}

Decimal Notation

s = - 7.88675 \dots, s = - 2.11324 \dots

Solution steps

- 3 s^{2} - 30 s - 50 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 ( - 3 ) ( - 50 )}{2 ( - 3 )}

(- 30)^{2} - 4 (- 3) (- 50) = 103

s_{1, 2} = \frac{- ( - 30 ) \pm 10 3}{2 ( - 3 )}

Separate the solutions

s_{1} = \frac{- ( - 30 ) + 10 3}{2 ( - 3 )}, s_{2} = \frac{- ( - 30 ) - 10 3}{2 ( - 3 )}

s = \frac{- ( - 30 ) + 10 3}{2 ( - 3 )} : - \frac{5 ( 3 + 3 )}{3}

s = \frac{- ( - 30 ) - 10 3}{2 ( - 3 )} : - \frac{5 ( 3 - 3 )}{3}

The solutions to the quadratic equation are:

s = - \frac{5 ( 3 + 3 )}{3}, s = - \frac{5 ( 3 - 3 )}{3}

x, f (x^{2} + x + 2) = f + 1

\frac{1}{4} (7 - 4 x^{2}) + 4 x + \frac{1 - 8 x}{2} = 0

x, x^{2} = 4 y^{2}

- 3 x^{2} + 12 x + 6 = 0

2 a^{2} + 3 a + 1 = 0

What are the solutions to the equation -3s^2-30s-50=0 ?
The solutions to the equation -3s^2-30s-50=0 are s=-(5(3+sqrt(3)))/3 ,s=-(5(3-sqrt(3)))/3
Find the zeros of -3s^2-30s-50=0
The zeros of -3s^2-30s-50=0 are s=-(5(3+sqrt(3)))/3 ,s=-(5(3-sqrt(3)))/3