What is the answer to solvefor x,(x-4)(2x-3)=2x^2+px+12 ?

The answer to solvefor x,(x-4)(2x-3)=2x^2+px+12 is x=0

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solvefor x,(x-4)(2x-3)=2x^2+px+12

solve for

x, (x - 4) (2 x - 3) = 2 x^{2} + p x + 12

x = 0

Solution steps

(x - 4) (2 x - 3) = 2 x^{2} + p x + 12

Expand

(x - 4) (2 x - 3) : 2 x^{2} - 11 x + 12

2 x^{2} - 11 x + 12 = 2 x^{2} + p x + 12

Move

12

to the right side

2 x^{2} - 11 x = 2 x^{2} + x p

Subtract

2 x^{2} + x p

from both sides

2 x^{2} - 11 x - (2 x^{2} + x p) = 2 x^{2} + x p - (2 x^{2} + x p)

Simplify

- x p - 11 x = 0

Factor

- x p - 11 x : - x (p + 11)

- x (p + 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0

(4 ka + 4 a + 1) (k + 1) = 4 k^{2} - 7 k - 11

x^{2} - 16 x + 26 = - 24

x, x^{2} = 2 p y

x, f = x^{2} g

(3 x + 5)^{2} = 4

What is the answer to solvefor x,(x-4)(2x-3)=2x^2+px+12 ?
The answer to solvefor x,(x-4)(2x-3)=2x^2+px+12 is x=0