What are the solutions to the equation t^2-3t-2=0 ?

The solutions to the equation t^2-3t-2=0 are t=(3+sqrt(17))/2 ,t=(3-sqrt(17))/2

Find the zeros of t^2-3t-2=0

The zeros of t^2-3t-2=0 are t=(3+sqrt(17))/2 ,t=(3-sqrt(17))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^{2} - 3 t - 2 = 0

t = \frac{3 + 17}{2}, t = \frac{3 - 17}{2}

Decimal Notation

t = 3.56155 \dots, t = - 0.56155 \dots

Solution steps

t^{2} - 3 t - 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 2) = 17

t_{1, 2} = \frac{- ( - 3 ) \pm 17}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 17}{2 \cdot 1}, t_{2} = \frac{- ( - 3 ) - 17}{2 \cdot 1}

t = \frac{- ( - 3 ) + 17}{2 \cdot 1} : \frac{3 + 17}{2}

t = \frac{- ( - 3 ) - 17}{2 \cdot 1} : \frac{3 - 17}{2}

The solutions to the quadratic equation are:

t = \frac{3 + 17}{2}, t = \frac{3 - 17}{2}

x, (x - m)^{2} = 6 - m

(2 x + 15) (9 + 2 x) - (15) (9) = 100

x^{2} + 8 (\frac{- 8 - 3 x}{4}) = 0

(x + 6)^{2} + 3 (5 x - 6) = - 2 (x^{2} + x)

X^{2} + X - 1 = 3 (X - 4)^{2} + 2

What are the solutions to the equation t^2-3t-2=0 ?
The solutions to the equation t^2-3t-2=0 are t=(3+sqrt(17))/2 ,t=(3-sqrt(17))/2
Find the zeros of t^2-3t-2=0
The zeros of t^2-3t-2=0 are t=(3+sqrt(17))/2 ,t=(3-sqrt(17))/2