What are the solutions to the equation -0.25x^2-83x+1032=0 ?

The solutions to the equation -0.25x^2-83x+1032=0 are x=-344,x=12

Find the zeros of -0.25x^2-83x+1032=0

The zeros of -0.25x^2-83x+1032=0 are x=-344,x=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 0.25 x^{2} - 83 x + 1032 = 0

x = - 344, x = 12

Solution steps

- 0.25 x^{2} - 83 x + 1032 = 0

Multiply both sides by

100

- 25 x^{2} - 8300 x + 103200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8300 ) \pm ( - 8300 ) ^{2} - 4 ( - 25 ) \cdot 103200}{2 ( - 25 )}

(- 8300)^{2} - 4 (- 25) \cdot 103200 = 8900

x_{1, 2} = \frac{- ( - 8300 ) \pm 8900}{2 ( - 25 )}

Separate the solutions

x_{1} = \frac{- ( - 8300 ) + 8900}{2 ( - 25 )}, x_{2} = \frac{- ( - 8300 ) - 8900}{2 ( - 25 )}

x = \frac{- ( - 8300 ) + 8900}{2 ( - 25 )} : - 344

x = \frac{- ( - 8300 ) - 8900}{2 ( - 25 )} : 12

The solutions to the quadratic equation are:

x = - 344, x = 12

- 22 = - 6 x^{2} + 29 x

1 + 0.4 x - 0.21 x^{2} = 0

- 2 w^{2} + 7 w - 4 = - 3 w^{2}

r^{2} - 4 r = 12

0 = - x^{2} + x

What are the solutions to the equation -0.25x^2-83x+1032=0 ?
The solutions to the equation -0.25x^2-83x+1032=0 are x=-344,x=12
Find the zeros of -0.25x^2-83x+1032=0
The zeros of -0.25x^2-83x+1032=0 are x=-344,x=12