What are the solutions to the equation -22=-6x^2+29x ?

The solutions to the equation -22=-6x^2+29x are x=-2/3 ,x= 11/2

Find the zeros of -22=-6x^2+29x

The zeros of -22=-6x^2+29x are x=-2/3 ,x= 11/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 22 = - 6 x^{2} + 29 x

x = - \frac{2}{3}, x = \frac{11}{2}

Decimal Notation

x = - 0.66666 \dots, x = 5.5

Solution steps

- 22 = - 6 x^{2} + 29 x

Switch sides

- 6 x^{2} + 29 x = - 22

Move

22

to the left side

- 6 x^{2} + 29 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 ( - 6 ) \cdot 22}{2 ( - 6 )}

2 9^{2} - 4 (- 6) \cdot 22 = 37

x_{1, 2} = \frac{- 29 \pm 37}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 29 + 37}{2 ( - 6 )}, x_{2} = \frac{- 29 - 37}{2 ( - 6 )}

x = \frac{- 29 + 37}{2 ( - 6 )} : - \frac{2}{3}

x = \frac{- 29 - 37}{2 ( - 6 )} : \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = \frac{11}{2}

1 + 0.4 x - 0.21 x^{2} = 0

- 2 w^{2} + 7 w - 4 = - 3 w^{2}

r^{2} - 4 r = 12

0 = - x^{2} + x

4 (- 3 x + x^{2}) + 9 = 0

What are the solutions to the equation -22=-6x^2+29x ?
The solutions to the equation -22=-6x^2+29x are x=-2/3 ,x= 11/2
Find the zeros of -22=-6x^2+29x
The zeros of -22=-6x^2+29x are x=-2/3 ,x= 11/2