What are the solutions to the equation 4(-3x+x^2)+9=0 ?

The solutions to the equation 4(-3x+x^2)+9=0 are x= 3/2

Find the zeros of 4(-3x+x^2)+9=0

The zeros of 4(-3x+x^2)+9=0 are x= 3/2

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4 (- 3 x + x^{2}) + 9 = 0

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

4 (- 3 x + x^{2}) + 9 = 0

Expand

4 (- 3 x + x^{2}) + 9 : - 12 x + 4 x^{2} + 9

- 12 x + 4 x^{2} + 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

36 x^{2} - 24 x - 12 = 0

x, b^{2} x^{2} - a^{2} y^{2} = 3 a^{2} b^{2}

x^{2} - 9 x - 43 = 27

- 2 x^{2} + 2 x + 15 = 0

G (x) = - 0.003 x^{2} + 6 x - 1700

What are the solutions to the equation 4(-3x+x^2)+9=0 ?
The solutions to the equation 4(-3x+x^2)+9=0 are x= 3/2
Find the zeros of 4(-3x+x^2)+9=0
The zeros of 4(-3x+x^2)+9=0 are x= 3/2