What are the solutions to the equation -2x^2+2x+15=0 ?

The solutions to the equation -2x^2+2x+15=0 are x=-(-1+sqrt(31))/2 ,x=(1+sqrt(31))/2

Find the zeros of -2x^2+2x+15=0

The zeros of -2x^2+2x+15=0 are x=-(-1+sqrt(31))/2 ,x=(1+sqrt(31))/2

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- 2 x^{2} + 2 x + 15 = 0

x = - \frac{- 1 + 31}{2}, x = \frac{1 + 31}{2}

Decimal Notation

x = - 2.28388 \dots, x = 3.28388 \dots

Solution steps

- 2 x^{2} + 2 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 2 ) \cdot 15}{2 ( - 2 )}

2^{2} - 4 (- 2) \cdot 15 = 231

x_{1, 2} = \frac{- 2 \pm 2 31}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 31}{2 ( - 2 )}, x_{2} = \frac{- 2 - 2 31}{2 ( - 2 )}

x = \frac{- 2 + 2 31}{2 ( - 2 )} : - \frac{- 1 + 31}{2}

x = \frac{- 2 - 2 31}{2 ( - 2 )} : \frac{1 + 31}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 31}{2}, x = \frac{1 + 31}{2}

G (x) = - 0.003 x^{2} + 6 x - 1700

9 x^{2} - 18 x + 13

- x^{2} - 13 x = 6

3 x^{2} - 6 x + 12

266 = 0.68 \cdot 100 \cdot X \cdot 1.79 \cdot (4.75 - 0.4 \cdot X)

What are the solutions to the equation -2x^2+2x+15=0 ?
The solutions to the equation -2x^2+2x+15=0 are x=-(-1+sqrt(31))/2 ,x=(1+sqrt(31))/2
Find the zeros of -2x^2+2x+15=0
The zeros of -2x^2+2x+15=0 are x=-(-1+sqrt(31))/2 ,x=(1+sqrt(31))/2