What are the solutions to the equation -x^2-13x=6 ?

The solutions to the equation -x^2-13x=6 are x=-(13+sqrt(145))/2 ,x=-(13-sqrt(145))/2

Find the zeros of -x^2-13x=6

The zeros of -x^2-13x=6 are x=-(13+sqrt(145))/2 ,x=-(13-sqrt(145))/2

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- x^{2} - 13 x = 6

x = - \frac{13 + 145}{2}, x = - \frac{13 - 145}{2}

Decimal Notation

x = - 12.52079 \dots, x = - 0.47920 \dots

Solution steps

- x^{2} - 13 x = 6

Move

6

to the left side

- x^{2} - 13 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

(- 13)^{2} - 4 (- 1) (- 6) = 145

x_{1, 2} = \frac{- ( - 13 ) \pm 145}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 145}{2 ( - 1 )}, x_{2} = \frac{- ( - 13 ) - 145}{2 ( - 1 )}

x = \frac{- ( - 13 ) + 145}{2 ( - 1 )} : - \frac{13 + 145}{2}

x = \frac{- ( - 13 ) - 145}{2 ( - 1 )} : - \frac{13 - 145}{2}

The solutions to the quadratic equation are:

x = - \frac{13 + 145}{2}, x = - \frac{13 - 145}{2}

3 x^{2} - 6 x + 12

266 = 0.68 \cdot 100 \cdot X \cdot 1.79 \cdot (4.75 - 0.4 \cdot X)

x, 2 (x + y) = 1 + (x - y)^{2}

2 x^{2} + 9 - 10 = 0

- 5 x^{2} - 40 x + 45 = 0

What are the solutions to the equation -x^2-13x=6 ?
The solutions to the equation -x^2-13x=6 are x=-(13+sqrt(145))/2 ,x=-(13-sqrt(145))/2
Find the zeros of -x^2-13x=6
The zeros of -x^2-13x=6 are x=-(13+sqrt(145))/2 ,x=-(13-sqrt(145))/2