What are the solutions to the equation completesquare x^2-3x-4=0 ?

The solutions to the equation completesquare x^2-3x-4=0 are x=4,x=-1

Find the zeros of completesquare x^2-3x-4=0

The zeros of completesquare x^2-3x-4=0 are x=4,x=-1

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x^{2} - 3 x - 4 = 0

x = 4, x = - 1

Solution steps

x^{2} - 3 x - 4 = 0

Move

4

to the right side

x^{2} - 3 x = 4

Rewrite in the form

(x + a)^{2} = b

(x - \frac{3}{2})^{2} = \frac{25}{4}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{3}{2} = \frac{25}{4} : x = 4

Solve

x - \frac{3}{2} = - \frac{25}{4} : x = - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

4.9 t^{2} + 8 t - 25 = 0

x, z^{2} = 4 + 4 (x^{2} + y^{2})

2 (x - 1)^{2} - 36 = 0

(2 x + 1) (x - 7) = 0

x, x^{2} + m x + m + 5 = 0

What are the solutions to the equation completesquare x^2-3x-4=0 ?
The solutions to the equation completesquare x^2-3x-4=0 are x=4,x=-1
Find the zeros of completesquare x^2-3x-4=0
The zeros of completesquare x^2-3x-4=0 are x=4,x=-1