What are the solutions to the equation 2(x-1)^2-36=0 ?

The solutions to the equation 2(x-1)^2-36=0 are x=3sqrt(2)+1,x=-3sqrt(2)+1

Find the zeros of 2(x-1)^2-36=0

The zeros of 2(x-1)^2-36=0 are x=3sqrt(2)+1,x=-3sqrt(2)+1

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2 (x - 1)^{2} - 36 = 0

x = 32 + 1, x = - 32 + 1

Decimal Notation

x = 5.24264 \dots, x = - 3.24264 \dots

Solution steps

2 (x - 1)^{2} - 36 = 0

Move

36

to the right side

2 (x - 1)^{2} = 36

Divide both sides by

2

(x - 1)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 18 : x = 32 + 1

Solve

x - 1 = - 18 : x = - 32 + 1

The solutions to the quadratic equation are:

x = 32 + 1, x = - 32 + 1

(2 x + 1) (x - 7) = 0

x, x^{2} + m x + m + 5 = 0

λ^{2} - 4 λ + 3 = 0

x, x^{2} y - 4 y + 4 = 0

(x - 3)^{3} = x^{3} + 5

What are the solutions to the equation 2(x-1)^2-36=0 ?
The solutions to the equation 2(x-1)^2-36=0 are x=3sqrt(2)+1,x=-3sqrt(2)+1
Find the zeros of 2(x-1)^2-36=0
The zeros of 2(x-1)^2-36=0 are x=3sqrt(2)+1,x=-3sqrt(2)+1