What are the solutions to the equation 3x^2-18x+225=6 ?

The solutions to the equation 3x^2-18x+225=6 are x=3+8i,x=3-8i

Find the zeros of 3x^2-18x+225=6

The zeros of 3x^2-18x+225=6 are x=3+8i,x=3-8i

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3 x^{2} - 18 x + 225 = 6

x = 3 + 8 i, x = 3 - 8 i

Solution steps

3 x^{2} - 18 x + 225 = 6

Move

6

to the left side

3 x^{2} - 18 x + 219 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 219}{2 \cdot 3}

Simplify

(- 18)^{2} - 4 \cdot 3 \cdot 219 : 48 i

x_{1, 2} = \frac{- ( - 18 ) \pm 48 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 48 i}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 48 i}{2 \cdot 3}

x = \frac{- ( - 18 ) + 48 i}{2 \cdot 3} : 3 + 8 i

x = \frac{- ( - 18 ) - 48 i}{2 \cdot 3} : 3 - 8 i

The solutions to the quadratic equation are:

x = 3 + 8 i, x = 3 - 8 i

104 = 8 x

(4 p + 4)^{2} - 3 (4 p + 4) + 4 = 0

6 = p + 3

6 x^{2} + 13 x - 8 = 0

31 < 3 x + 4

What are the solutions to the equation 3x^2-18x+225=6 ?
The solutions to the equation 3x^2-18x+225=6 are x=3+8i,x=3-8i
Find the zeros of 3x^2-18x+225=6
The zeros of 3x^2-18x+225=6 are x=3+8i,x=3-8i