What are the solutions to the equation (4p+4)^2-3(4p+4)+4=0 ?

The solutions to the equation (4p+4)^2-3(4p+4)+4=0 are p=-5/8+i(sqrt(7))/8 ,p=-5/8-i(sqrt(7))/8

Find the zeros of (4p+4)^2-3(4p+4)+4=0

The zeros of (4p+4)^2-3(4p+4)+4=0 are p=-5/8+i(sqrt(7))/8 ,p=-5/8-i(sqrt(7))/8

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(4 p + 4)^{2} - 3 (4 p + 4) + 4 = 0

p = - \frac{5}{8} + i \frac{7}{8}, p = - \frac{5}{8} - i \frac{7}{8}

Solution steps

(4 p + 4)^{2} - 3 (4 p + 4) + 4 = 0

Expand

(4 p + 4)^{2} - 3 (4 p + 4) + 4 : 16 p^{2} + 20 p + 8

16 p^{2} + 20 p + 8 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 16 \cdot 8}{2 \cdot 16}

Simplify

2 0^{2} - 4 \cdot 16 \cdot 8 : 47 i

p_{1, 2} = \frac{- 20 \pm 4 7 i}{2 \cdot 16}

Separate the solutions

p_{1} = \frac{- 20 + 4 7 i}{2 \cdot 16}, p_{2} = \frac{- 20 - 4 7 i}{2 \cdot 16}

p = \frac{- 20 + 4 7 i}{2 \cdot 16} : - \frac{5}{8} + i \frac{7}{8}

p = \frac{- 20 - 4 7 i}{2 \cdot 16} : - \frac{5}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

p = - \frac{5}{8} + i \frac{7}{8}, p = - \frac{5}{8} - i \frac{7}{8}

6 = p + 3

6 x^{2} + 13 x - 8 = 0

31 < 3 x + 4

m^{2} + 16 = 0

x > - 5 or x < - 2

What are the solutions to the equation (4p+4)^2-3(4p+4)+4=0 ?
The solutions to the equation (4p+4)^2-3(4p+4)+4=0 are p=-5/8+i(sqrt(7))/8 ,p=-5/8-i(sqrt(7))/8
Find the zeros of (4p+4)^2-3(4p+4)+4=0
The zeros of (4p+4)^2-3(4p+4)+4=0 are p=-5/8+i(sqrt(7))/8 ,p=-5/8-i(sqrt(7))/8