What are the solutions to the equation 9x^2+28x+50=0 ?

The solutions to the equation 9x^2+28x+50=0 are x=-14/9+i(sqrt(254))/9 ,x=-14/9-i(sqrt(254))/9

Find the zeros of 9x^2+28x+50=0

The zeros of 9x^2+28x+50=0 are x=-14/9+i(sqrt(254))/9 ,x=-14/9-i(sqrt(254))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 28 x + 50 = 0

x = - \frac{14}{9} + i \frac{254}{9}, x = - \frac{14}{9} - i \frac{254}{9}

Solution steps

9 x^{2} + 28 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 9 \cdot 50}{2 \cdot 9}

Simplify

2 8^{2} - 4 \cdot 9 \cdot 50 : 2254 i

x_{1, 2} = \frac{- 28 \pm 2 254 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 28 + 2 254 i}{2 \cdot 9}, x_{2} = \frac{- 28 - 2 254 i}{2 \cdot 9}

x = \frac{- 28 + 2 254 i}{2 \cdot 9} : - \frac{14}{9} + i \frac{254}{9}

x = \frac{- 28 - 2 254 i}{2 \cdot 9} : - \frac{14}{9} - i \frac{254}{9}

The solutions to the quadratic equation are:

x = - \frac{14}{9} + i \frac{254}{9}, x = - \frac{14}{9} - i \frac{254}{9}

36 x^{2} - 121 = 0

A = (x + 8)^{2} + (x - 8)^{2} - (x + 2) (x - 2)

x^{2} - 3 x - 1 = 0

2 x (x - 4) = 12

2 x^{2} - 2 x - 30 = - 2 x^{2} - 19

What are the solutions to the equation 9x^2+28x+50=0 ?
The solutions to the equation 9x^2+28x+50=0 are x=-14/9+i(sqrt(254))/9 ,x=-14/9-i(sqrt(254))/9
Find the zeros of 9x^2+28x+50=0
The zeros of 9x^2+28x+50=0 are x=-14/9+i(sqrt(254))/9 ,x=-14/9-i(sqrt(254))/9