What are the solutions to the equation factor 2x^2-7x-15=0 ?

The solutions to the equation factor 2x^2-7x-15=0 are x=-3/2 ,x=5

Find the zeros of factor 2x^2-7x-15=0

The zeros of factor 2x^2-7x-15=0 are x=-3/2 ,x=5

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2 x^{2} - 7 x - 15 = 0

x = - \frac{3}{2}, x = 5

Decimal Notation

x = - 1.5, x = 5

Solution steps

2 x^{2} - 7 x - 15 = 0

Factor

2 x^{2} - 7 x - 15 : (2 x + 3) (x - 5)

(2 x + 3) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x - 5 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 5

x (x + 15) = 1924

x, x^{2} + y^{2} + 2 x y - 7 x - 6 y + 10 = 0

15 x^{2} + 5 x - 6 = 0

2 x (x + 2) + 2 x (x + 1) = x^{2} + 4

\frac{x ^{2}}{4} - \frac{3 x}{2} + 2 = 0

What are the solutions to the equation factor 2x^2-7x-15=0 ?
The solutions to the equation factor 2x^2-7x-15=0 are x=-3/2 ,x=5
Find the zeros of factor 2x^2-7x-15=0
The zeros of factor 2x^2-7x-15=0 are x=-3/2 ,x=5