What are the solutions to the equation 9x^2-4x+2=0 ?

The solutions to the equation 9x^2-4x+2=0 are x= 2/9+i(sqrt(14))/9 ,x= 2/9-i(sqrt(14))/9

Find the zeros of 9x^2-4x+2=0

The zeros of 9x^2-4x+2=0 are x= 2/9+i(sqrt(14))/9 ,x= 2/9-i(sqrt(14))/9

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9 x^{2} - 4 x + 2 = 0

x = \frac{2}{9} + i \frac{14}{9}, x = \frac{2}{9} - i \frac{14}{9}

Solution steps

9 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

(- 4)^{2} - 4 \cdot 9 \cdot 2 : 214 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 14 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 9}, x_{2} = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 9}

x = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 9} : \frac{2}{9} + i \frac{14}{9}

x = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 9} : \frac{2}{9} - i \frac{14}{9}

The solutions to the quadratic equation are:

x = \frac{2}{9} + i \frac{14}{9}, x = \frac{2}{9} - i \frac{14}{9}

\frac{x}{2} \geq \frac{8}{x + 1} + 7

- 5.5 - 3 y - 6.7 - y = - 3 y + 8.1

6 x - 11 = 5 x + 4

4 x^{2} - 27 x - 7 = 0

lo g_{3} (\frac{1}{3}) = x

What are the solutions to the equation 9x^2-4x+2=0 ?
The solutions to the equation 9x^2-4x+2=0 are x= 2/9+i(sqrt(14))/9 ,x= 2/9-i(sqrt(14))/9
Find the zeros of 9x^2-4x+2=0
The zeros of 9x^2-4x+2=0 are x= 2/9+i(sqrt(14))/9 ,x= 2/9-i(sqrt(14))/9