What are the solutions to the equation 5=2(x-2)(x+3)+(x-3)(x+3) ?

The solutions to the equation 5=2(x-2)(x+3)+(x-3)(x+3) are x=(-1+sqrt(79))/3 ,x=-(1+sqrt(79))/3

Find the zeros of 5=2(x-2)(x+3)+(x-3)(x+3)

The zeros of 5=2(x-2)(x+3)+(x-3)(x+3) are x=(-1+sqrt(79))/3 ,x=-(1+sqrt(79))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 = 2 (x - 2) (x + 3) + (x - 3) (x + 3)

x = \frac{- 1 + 79}{3}, x = - \frac{1 + 79}{3}

Decimal Notation

x = 2.62939 \dots, x = - 3.29606 \dots

Solution steps

5 = 2 (x - 2) (x + 3) + (x - 3) (x + 3)

Expand

2 (x - 2) (x + 3) + (x - 3) (x + 3) : 3 x^{2} + 2 x - 21

5 = 3 x^{2} + 2 x - 21

Switch sides

3 x^{2} + 2 x - 21 = 5

Move

5

to the left side

3 x^{2} + 2 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 26 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 26) = 279

x_{1, 2} = \frac{- 2 \pm 2 79}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 79}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 79}{2 \cdot 3}

x = \frac{- 2 + 2 79}{2 \cdot 3} : \frac{- 1 + 79}{3}

x = \frac{- 2 - 2 79}{2 \cdot 3} : - \frac{1 + 79}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 79}{3}, x = - \frac{1 + 79}{3}

x (x - 11) = 3

5 m^{2} + m = 120

x^{2} + 21 x + 19 = 10 x - 5

10 x^{2} + 13 x - 3 = 0

- 0.5 q^{2} + 620 = 30 q + 270

What are the solutions to the equation 5=2(x-2)(x+3)+(x-3)(x+3) ?
The solutions to the equation 5=2(x-2)(x+3)+(x-3)(x+3) are x=(-1+sqrt(79))/3 ,x=-(1+sqrt(79))/3
Find the zeros of 5=2(x-2)(x+3)+(x-3)(x+3)
The zeros of 5=2(x-2)(x+3)+(x-3)(x+3) are x=(-1+sqrt(79))/3 ,x=-(1+sqrt(79))/3