What are the solutions to the equation 0.02(0.5x^2-x)=0,25 ?

The solutions to the equation 0.02(0.5x^2-x)=0,25 are x=0,x=2

Find the zeros of 0.02(0.5x^2-x)=0,25

The zeros of 0.02(0.5x^2-x)=0,25 are x=0,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0.02 (0.5 x^{2} - x) = 0, 25

x = 0, x = 2

Solution steps

0.02 (0.5 x^{2} - x) = 0, 25

Factor

0.02 (0.5 x^{2} - x) : 0.02 x (0.5 x - 1)

0.02 x (0.5 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 0.5 x - 1 = 0

Solve

0.5 x - 1 = 0 : x = 2

The solutions to the quadratic equation are:

x = 0, x = 2

x, zy = x^{2}

x^{2} - 7 x = - 3

5 p^{2} - 14 p = 24

(x) = 300 - x + \frac{( x - 100 ) ^{2}}{250}

x^{2} + (x + 3)^{2} = 225

What are the solutions to the equation 0.02(0.5x^2-x)=0,25 ?
The solutions to the equation 0.02(0.5x^2-x)=0,25 are x=0,x=2
Find the zeros of 0.02(0.5x^2-x)=0,25
The zeros of 0.02(0.5x^2-x)=0,25 are x=0,x=2