What are the solutions to the equation 5p^2-14p=24 ?

The solutions to the equation 5p^2-14p=24 are p=4,p=-6/5

Find the zeros of 5p^2-14p=24

The zeros of 5p^2-14p=24 are p=4,p=-6/5

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5 p^{2} - 14 p = 24

p = 4, p = - \frac{6}{5}

Decimal Notation

p = 4, p = - 1.2

Solution steps

5 p^{2} - 14 p = 24

Move

24

to the left side

5 p^{2} - 14 p - 24 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

(- 14)^{2} - 4 \cdot 5 (- 24) = 26

p_{1, 2} = \frac{- ( - 14 ) \pm 26}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- ( - 14 ) + 26}{2 \cdot 5}, p_{2} = \frac{- ( - 14 ) - 26}{2 \cdot 5}

p = \frac{- ( - 14 ) + 26}{2 \cdot 5} : 4

p = \frac{- ( - 14 ) - 26}{2 \cdot 5} : - \frac{6}{5}

The solutions to the quadratic equation are:

p = 4, p = - \frac{6}{5}

(x) = 300 - x + \frac{( x - 100 ) ^{2}}{250}

x^{2} + (x + 3)^{2} = 225

3 x^{2} - 18 x + 14 x = 33

x, f = s g n (x^{2} - 1)

(4 - x)^{2} - 4 = 0

What are the solutions to the equation 5p^2-14p=24 ?
The solutions to the equation 5p^2-14p=24 are p=4,p=-6/5
Find the zeros of 5p^2-14p=24
The zeros of 5p^2-14p=24 are p=4,p=-6/5