What are the solutions to the equation (4-x)^2-4=0 ?

The solutions to the equation (4-x)^2-4=0 are x=2,x=6

Find the zeros of (4-x)^2-4=0

The zeros of (4-x)^2-4=0 are x=2,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 - x)^{2} - 4 = 0

x = 2, x = 6

Solution steps

(4 - x)^{2} - 4 = 0

Move

4

to the right side

(4 - x)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 - x = 4 : x = 2

Solve

4 - x = - 4 : x = 6

The solutions to the quadratic equation are:

x = 2, x = 6

(x + 2)^{4} = x^{4} + 8 x^{3} + 8

A = \frac{3}{4} x^{2}

(x + 2)^{2} - 9 = - 5

3 x^{2} + 17 x - 10 = 3 x - 5

7 x^{2} + 8 x + 6 = 0

What are the solutions to the equation (4-x)^2-4=0 ?
The solutions to the equation (4-x)^2-4=0 are x=2,x=6
Find the zeros of (4-x)^2-4=0
The zeros of (4-x)^2-4=0 are x=2,x=6