What are the solutions to the equation y^2-2y+6=0 ?

The solutions to the equation y^2-2y+6=0 are y=1+sqrt(5)i,y=1-sqrt(5)i

Find the zeros of y^2-2y+6=0

The zeros of y^2-2y+6=0 are y=1+sqrt(5)i,y=1-sqrt(5)i

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y^{2} - 2 y + 6 = 0

y = 1 + 5 i, y = 1 - 5 i

Solution steps

y^{2} - 2 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 6 : 25 i

y_{1, 2} = \frac{- ( - 2 ) \pm 2 5 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 5 i}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 5 i}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 5 i}{2 \cdot 1} : 1 + 5 i

y = \frac{- ( - 2 ) - 2 5 i}{2 \cdot 1} : 1 - 5 i

The solutions to the quadratic equation are:

y = 1 + 5 i, y = 1 - 5 i

z^{2} - 7 z + 4 = 0

5 x^{2} + 23 x = 2 x - 4

x, x^{2} y^{2} = 2

r^{2} + 8 r + 784 = 0

4 x^{2} - 11 = 53

What are the solutions to the equation y^2-2y+6=0 ?
The solutions to the equation y^2-2y+6=0 are y=1+sqrt(5)i,y=1-sqrt(5)i
Find the zeros of y^2-2y+6=0
The zeros of y^2-2y+6=0 are y=1+sqrt(5)i,y=1-sqrt(5)i