What are the solutions to the equation 0=45-16d+d^2 ?

The solutions to the equation 0=45-16d+d^2 are d=8+sqrt(19),d=8-sqrt(19)

Find the zeros of 0=45-16d+d^2

The zeros of 0=45-16d+d^2 are d=8+sqrt(19),d=8-sqrt(19)

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0 = 45 - 16 d + d^{2}

d = 8 + 19, d = 8 - 19

Decimal Notation

d = 12.35889 \dots, d = 3.64110 \dots

Solution steps

0 = 45 - 16 d + d^{2}

Switch sides

45 - 16 d + d^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

d^{2} - 16 d + 45 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 45 = 219

d_{1, 2} = \frac{- ( - 16 ) \pm 2 19}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- ( - 16 ) + 2 19}{2 \cdot 1}, d_{2} = \frac{- ( - 16 ) - 2 19}{2 \cdot 1}

d = \frac{- ( - 16 ) + 2 19}{2 \cdot 1} : 8 + 19

d = \frac{- ( - 16 ) - 2 19}{2 \cdot 1} : 8 - 19

The solutions to the quadratic equation are:

d = 8 + 19, d = 8 - 19

- 0.03 x^{2} - 35 x + 712 = 0

y^{2} - 3 y - 28 = 0

x, (x - 1) (3 x + 2 y - 1) = C

x^{2} - 4 x + 5 = 0

x (x + 8) = 3

What are the solutions to the equation 0=45-16d+d^2 ?
The solutions to the equation 0=45-16d+d^2 are d=8+sqrt(19),d=8-sqrt(19)
Find the zeros of 0=45-16d+d^2
The zeros of 0=45-16d+d^2 are d=8+sqrt(19),d=8-sqrt(19)