What are the solutions to the equation s^2-1=3 ?

The solutions to the equation s^2-1=3 are s=2,s=-2

Find the zeros of s^2-1=3

The zeros of s^2-1=3 are s=2,s=-2

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s^{2} - 1 = 3

s = 2, s = - 2

Solution steps

s^{2} - 1 = 3

Move

1

to the right side

s^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = 4, s = - 4

4 = 2

- 4 = - 2

s = 2, s = - 2

3 x^{2} - 32 x + 77 = 0

\frac{3}{4} x^{2} - 12 = 0

\frac{3}{4} (x^{2} - 27) = - \frac{9 x}{2}

x, x^{2} + (s + t) x + s t = 0

x^{2} - 6 x + 5 = 12

What are the solutions to the equation s^2-1=3 ?
The solutions to the equation s^2-1=3 are s=2,s=-2
Find the zeros of s^2-1=3
The zeros of s^2-1=3 are s=2,s=-2