What are the solutions to the equation 3a^2-7a+2=0 ?

The solutions to the equation 3a^2-7a+2=0 are a=2,a= 1/3

Find the zeros of 3a^2-7a+2=0

The zeros of 3a^2-7a+2=0 are a=2,a= 1/3

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3 a^{2} - 7 a + 2 = 0

a = 2, a = \frac{1}{3}

Decimal Notation

a = 2, a = 0.33333 \dots

Solution steps

3 a^{2} - 7 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 2 = 5

a_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 3}, a_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 3}

a = \frac{- ( - 7 ) + 5}{2 \cdot 3} : 2

a = \frac{- ( - 7 ) - 5}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

a = 2, a = \frac{1}{3}

4 t^{2} - 4 t + 1 = 0

4 k^{2} + 2 k = 0

\frac{x ( x - 1 )}{2} = \frac{2 x ^{2} + 3}{3}

x, x^{2} + y^{3} = 9

6 x^{2} + 2 x = - 5

What are the solutions to the equation 3a^2-7a+2=0 ?
The solutions to the equation 3a^2-7a+2=0 are a=2,a= 1/3
Find the zeros of 3a^2-7a+2=0
The zeros of 3a^2-7a+2=0 are a=2,a= 1/3