What are the solutions to the equation 4k^2+2k=0 ?

The solutions to the equation 4k^2+2k=0 are k=0,k=-1/2

Find the zeros of 4k^2+2k=0

The zeros of 4k^2+2k=0 are k=0,k=-1/2

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4 k^{2} + 2 k = 0

k = 0, k = - \frac{1}{2}

Decimal Notation

k = 0, k = - 0.5

Solution steps

4 k^{2} + 2 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

2^{2} - 4 \cdot 4 \cdot 0 = 2

k_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 2 + 2}{2 \cdot 4}, k_{2} = \frac{- 2 - 2}{2 \cdot 4}

k = \frac{- 2 + 2}{2 \cdot 4} : 0

k = \frac{- 2 - 2}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

k = 0, k = - \frac{1}{2}

\frac{x ( x - 1 )}{2} = \frac{2 x ^{2} + 3}{3}

x, x^{2} + y^{3} = 9

6 x^{2} + 2 x = - 5

0 = - 0.6 x^{2} + 3 x + 5

(x + 6) (x - 4) = - 16

What are the solutions to the equation 4k^2+2k=0 ?
The solutions to the equation 4k^2+2k=0 are k=0,k=-1/2
Find the zeros of 4k^2+2k=0
The zeros of 4k^2+2k=0 are k=0,k=-1/2