What are the solutions to the equation (x+6)(x-4)=-16 ?

The solutions to the equation (x+6)(x-4)=-16 are x=2,x=-4

Find the zeros of (x+6)(x-4)=-16

The zeros of (x+6)(x-4)=-16 are x=2,x=-4

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(x + 6) (x - 4) = - 16

x = 2, x = - 4

Solution steps

(x + 6) (x - 4) = - 16

Expand

(x + 6) (x - 4) : x^{2} + 2 x - 24

x^{2} + 2 x - 24 = - 16

Move

16

to the left side

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

(3 - x) (2 - x) - 2 = 0

m = (x + 7) 2 + (x - 10) (x - 4)

200 = 10 t + \frac{1}{2} \cdot 2 t^{2}

12 x^{2} - 8 x - 15 = 0

1^{2} + 2^{2} + 3^{2} + n^{2} = (3.14) (n + 1) (2 n + 1)

What are the solutions to the equation (x+6)(x-4)=-16 ?
The solutions to the equation (x+6)(x-4)=-16 are x=2,x=-4
Find the zeros of (x+6)(x-4)=-16
The zeros of (x+6)(x-4)=-16 are x=2,x=-4