What are the solutions to the equation x^2+14x+17=4 ?

The solutions to the equation x^2+14x+17=4 are x=-1,x=-13

Find the zeros of x^2+14x+17=4

The zeros of x^2+14x+17=4 are x=-1,x=-13

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x^{2} + 14 x + 17 = 4

x = - 1, x = - 13

Solution steps

x^{2} + 14 x + 17 = 4

Move

4

to the left side

x^{2} + 14 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 13 = 12

x_{1, 2} = \frac{- 14 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 12}{2 \cdot 1}, x_{2} = \frac{- 14 - 12}{2 \cdot 1}

x = \frac{- 14 + 12}{2 \cdot 1} : - 1

x = \frac{- 14 - 12}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 1, x = - 13

x, r^{2} = (y - r)^{2} + (\frac{x}{2})^{2}

88 = 151 x - 16 x^{2}

- x^{2} - 2 x = - 47

x^{2} + 10 x + 169 = 0

x^{2} - 14 x + 20

What are the solutions to the equation x^2+14x+17=4 ?
The solutions to the equation x^2+14x+17=4 are x=-1,x=-13
Find the zeros of x^2+14x+17=4
The zeros of x^2+14x+17=4 are x=-1,x=-13