What are the solutions to the equation (x^2)/2 =50.9-29,4y ?

The solutions to the equation (x^2)/2 =50.9-29,4y are x=sqrt(219/5),x=-sqrt(219/5)

Find the zeros of (x^2)/2 =50.9-29,4y

The zeros of (x^2)/2 =50.9-29,4y are x=sqrt(219/5),x=-sqrt(219/5)

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\frac{x ^{2}}{2} = 50.9 - 29, 4 y

x = \frac{219}{5}, x = - \frac{219}{5}

Decimal Notation

x = 6.61815 \dots, x = - 6.61815 \dots

Solution steps

\frac{x ^{2}}{2} = 50.9 - 29, 4 y

Subtract the numbers:

50.9 - 29 = 21.9

\frac{x ^{2}}{2} = 21.9

Multiply both sides by

2

x^{2} = 43.8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 43.8, x = - 43.8

43.8 = \frac{219}{5}

- 43.8 = - \frac{219}{5}

x = \frac{219}{5}, x = - \frac{219}{5}

- 2 x^{2} = 5

x^{2} + 4 x + \frac{28}{3} = 0

120 z^{2} - 500 z = 0

x (x + 1) = 600

(x) = - 3 (x - 2)^{2} + 4

What are the solutions to the equation (x^2)/2 =50.9-29,4y ?
The solutions to the equation (x^2)/2 =50.9-29,4y are x=sqrt(219/5),x=-sqrt(219/5)
Find the zeros of (x^2)/2 =50.9-29,4y
The zeros of (x^2)/2 =50.9-29,4y are x=sqrt(219/5),x=-sqrt(219/5)