What are the solutions to the equation 11(x-1)-2x^2=-3 ?

The solutions to the equation 11(x-1)-2x^2=-3 are x=(11-sqrt(57))/4 ,x=(11+sqrt(57))/4

Find the zeros of 11(x-1)-2x^2=-3

The zeros of 11(x-1)-2x^2=-3 are x=(11-sqrt(57))/4 ,x=(11+sqrt(57))/4

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11 (x - 1) - 2 x^{2} = - 3

x = \frac{11 - 57}{4}, x = \frac{11 + 57}{4}

Decimal Notation

x = 0.86254 \dots, x = 4.63745 \dots

Solution steps

11 (x - 1) - 2 x^{2} = - 3

Expand

11 (x - 1) - 2 x^{2} : 11 x - 11 - 2 x^{2}

11 x - 11 - 2 x^{2} = - 3

Move

3

to the left side

- 2 x^{2} + 11 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

1 1^{2} - 4 (- 2) (- 8) = 57

x_{1, 2} = \frac{- 11 \pm 57}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 11 + 57}{2 ( - 2 )}, x_{2} = \frac{- 11 - 57}{2 ( - 2 )}

x = \frac{- 11 + 57}{2 ( - 2 )} : \frac{11 - 57}{4}

x = \frac{- 11 - 57}{2 ( - 2 )} : \frac{11 + 57}{4}

The solutions to the quadratic equation are:

x = \frac{11 - 57}{4}, x = \frac{11 + 57}{4}

(2 x + 1) (x + 1) = 190

x^{2} + 8 x - 2

m^{2} + m - \frac{5}{16} = 0

\frac{\frac{( 16 xx )}{2}}{3} = \frac{7}{16000}

x, y (x^{2} + 2 x + 1) + 2 x^{2} + 4 x = (x + 2)^{2}

What are the solutions to the equation 11(x-1)-2x^2=-3 ?
The solutions to the equation 11(x-1)-2x^2=-3 are x=(11-sqrt(57))/4 ,x=(11+sqrt(57))/4
Find the zeros of 11(x-1)-2x^2=-3
The zeros of 11(x-1)-2x^2=-3 are x=(11-sqrt(57))/4 ,x=(11+sqrt(57))/4