What are the solutions to the equation solvefor t,r(t)=300t(1-t) ?

The solutions to the equation solvefor t,r(t)=300t(1-t) are t=0,t=-(r-300)/(300)

Find the zeros of solvefor t,r(t)=300t(1-t)

The zeros of solvefor t,r(t)=300t(1-t) are t=0,t=-(r-300)/(300)

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solve for

t, r (t) = 300 t (1 - t)

t = 0, t = - \frac{r - 300}{300}

Solution steps

r (t) = 300 t (1 - t)

Move

300 t (1 - t)

to the left side

r t - 300 t (1 - t) = 0

Factor

r t - 300 t (1 - t) : t (r - 300 (1 - t))

t (r - 300 (1 - t)) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or r - 300 (1 - t) = 0

Solve

r - 300 (1 - t) = 0 : t = - \frac{r - 300}{300}

The solutions to the quadratic equation are:

t = 0, t = - \frac{r - 300}{300}

u^{2} - u - 1 = 0

x, z = 3 x^{2} - x y + 2 y^{2} - 4 x - 7 y + 12

(x - 7) (x - 6) = 0

112 = - 16 t^{2} + 128 t

6 d^{2} - 3 d - 4 = d^{2}

What are the solutions to the equation solvefor t,r(t)=300t(1-t) ?
The solutions to the equation solvefor t,r(t)=300t(1-t) are t=0,t=-(r-300)/(300)
Find the zeros of solvefor t,r(t)=300t(1-t)
The zeros of solvefor t,r(t)=300t(1-t) are t=0,t=-(r-300)/(300)