What are the solutions to the equation a^2-a-7=0 ?

The solutions to the equation a^2-a-7=0 are a=(1+sqrt(29))/2 ,a=(1-sqrt(29))/2

Find the zeros of a^2-a-7=0

The zeros of a^2-a-7=0 are a=(1+sqrt(29))/2 ,a=(1-sqrt(29))/2

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a^{2} - a - 7 = 0

a = \frac{1 + 29}{2}, a = \frac{1 - 29}{2}

Decimal Notation

a = 3.19258 \dots, a = - 2.19258 \dots

Solution steps

a^{2} - a - 7 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 7) = 29

a_{1, 2} = \frac{- ( - 1 ) \pm 29}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 29}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 29}{2 \cdot 1}

a = \frac{- ( - 1 ) + 29}{2 \cdot 1} : \frac{1 + 29}{2}

a = \frac{- ( - 1 ) - 29}{2 \cdot 1} : \frac{1 - 29}{2}

The solutions to the quadratic equation are:

a = \frac{1 + 29}{2}, a = \frac{1 - 29}{2}

(3 x - 1)^{2} = 108

z^{2} - 4 z + 1 = 0

x, x^{2} + 4 x + 8 = - 2 y^{2}

2 a^{2} = 1

(x + 6) (x - 4) = 0

What are the solutions to the equation a^2-a-7=0 ?
The solutions to the equation a^2-a-7=0 are a=(1+sqrt(29))/2 ,a=(1-sqrt(29))/2
Find the zeros of a^2-a-7=0
The zeros of a^2-a-7=0 are a=(1+sqrt(29))/2 ,a=(1-sqrt(29))/2