What are the solutions to the equation (x+9)^2+8(x+9)+7=0 ?

The solutions to the equation (x+9)^2+8(x+9)+7=0 are x=-10,x=-16

Find the zeros of (x+9)^2+8(x+9)+7=0

The zeros of (x+9)^2+8(x+9)+7=0 are x=-10,x=-16

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(x + 9)^{2} + 8 (x + 9) + 7 = 0

x = - 10, x = - 16

Solution steps

(x + 9)^{2} + 8 (x + 9) + 7 = 0

Expand

(x + 9)^{2} + 8 (x + 9) + 7 : x^{2} + 26 x + 160

x^{2} + 26 x + 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 1 \cdot 160}{2 \cdot 1}

2 6^{2} - 4 \cdot 1 \cdot 160 = 6

x_{1, 2} = \frac{- 26 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 26 + 6}{2 \cdot 1}, x_{2} = \frac{- 26 - 6}{2 \cdot 1}

x = \frac{- 26 + 6}{2 \cdot 1} : - 10

x = \frac{- 26 - 6}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = - 10, x = - 16

- 45 = 0 + 10 t + \frac{1}{2} (- 9.8) t^{2}

4 (x - 7)^{2} + 25 = 69

3 r^{2} - 4050 r + 1362500 = 0

(3 x - 4)^{2} + 17 x = 35

- 6 x^{2} = - 14 x

What are the solutions to the equation (x+9)^2+8(x+9)+7=0 ?
The solutions to the equation (x+9)^2+8(x+9)+7=0 are x=-10,x=-16
Find the zeros of (x+9)^2+8(x+9)+7=0
The zeros of (x+9)^2+8(x+9)+7=0 are x=-10,x=-16