What are the solutions to the equation (3x-4)^2+17x=35 ?

The solutions to the equation (3x-4)^2+17x=35 are x=(7+sqrt(733))/(18),x=(7-sqrt(733))/(18)

Find the zeros of (3x-4)^2+17x=35

The zeros of (3x-4)^2+17x=35 are x=(7+sqrt(733))/(18),x=(7-sqrt(733))/(18)

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(3 x - 4)^{2} + 17 x = 35

x = \frac{7 + 733}{18}, x = \frac{7 - 733}{18}

Decimal Notation

x = 1.89299 \dots, x = - 1.11522 \dots

Solution steps

(3 x - 4)^{2} + 17 x = 35

Expand

(3 x - 4)^{2} + 17 x : 9 x^{2} - 7 x + 16

9 x^{2} - 7 x + 16 = 35

Move

35

to the left side

9 x^{2} - 7 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 9 ( - 19 )}{2 \cdot 9}

(- 7)^{2} - 4 \cdot 9 (- 19) = 733

x_{1, 2} = \frac{- ( - 7 ) \pm 733}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 733}{2 \cdot 9}, x_{2} = \frac{- ( - 7 ) - 733}{2 \cdot 9}

x = \frac{- ( - 7 ) + 733}{2 \cdot 9} : \frac{7 + 733}{18}

x = \frac{- ( - 7 ) - 733}{2 \cdot 9} : \frac{7 - 733}{18}

The solutions to the quadratic equation are:

x = \frac{7 + 733}{18}, x = \frac{7 - 733}{18}

- 6 x^{2} = - 14 x

x^{2} - 28 x - 60 = 0

n, d = \frac{n ( n - 3 )}{2}

2 b^{2} + 15 = 16 b

x^{2} - x - 6 = 6

What are the solutions to the equation (3x-4)^2+17x=35 ?
The solutions to the equation (3x-4)^2+17x=35 are x=(7+sqrt(733))/(18),x=(7-sqrt(733))/(18)
Find the zeros of (3x-4)^2+17x=35
The zeros of (3x-4)^2+17x=35 are x=(7+sqrt(733))/(18),x=(7-sqrt(733))/(18)