What are the solutions to the equation x^2-28x-60=0 ?

The solutions to the equation x^2-28x-60=0 are x=30,x=-2

Find the zeros of x^2-28x-60=0

The zeros of x^2-28x-60=0 are x=30,x=-2

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x^{2} - 28 x - 60 = 0

x = 30, x = - 2

Solution steps

x^{2} - 28 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

(- 28)^{2} - 4 \cdot 1 \cdot (- 60) = 32

x_{1, 2} = \frac{- ( - 28 ) \pm 32}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 32}{2 \cdot 1}, x_{2} = \frac{- ( - 28 ) - 32}{2 \cdot 1}

x = \frac{- ( - 28 ) + 32}{2 \cdot 1} : 30

x = \frac{- ( - 28 ) - 32}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 30, x = - 2

n, d = \frac{n ( n - 3 )}{2}

2 b^{2} + 15 = 16 b

x^{2} - x - 6 = 6

x, f^{- 1} (x) = x^{2} - 4

x^{2} - 18 x + 81 = 0

What are the solutions to the equation x^2-28x-60=0 ?
The solutions to the equation x^2-28x-60=0 are x=30,x=-2
Find the zeros of x^2-28x-60=0
The zeros of x^2-28x-60=0 are x=30,x=-2