What are the solutions to the equation 2b^2+15=16b ?

The solutions to the equation 2b^2+15=16b are b=(8+sqrt(34))/2 ,b=(8-sqrt(34))/2

Find the zeros of 2b^2+15=16b

The zeros of 2b^2+15=16b are b=(8+sqrt(34))/2 ,b=(8-sqrt(34))/2

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2 b^{2} + 15 = 16 b

b = \frac{8 + 34}{2}, b = \frac{8 - 34}{2}

Decimal Notation

b = 6.91547 \dots, b = 1.08452 \dots

Solution steps

2 b^{2} + 15 = 16 b

Move

16 b

to the left side

2 b^{2} + 15 - 16 b = 0

Write in the standard form

a x^{2} + b x + c = 0

2 b^{2} - 16 b + 15 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 15 = 234

b_{1, 2} = \frac{- ( - 16 ) \pm 2 34}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- ( - 16 ) + 2 34}{2 \cdot 2}, b_{2} = \frac{- ( - 16 ) - 2 34}{2 \cdot 2}

b = \frac{- ( - 16 ) + 2 34}{2 \cdot 2} : \frac{8 + 34}{2}

b = \frac{- ( - 16 ) - 2 34}{2 \cdot 2} : \frac{8 - 34}{2}

The solutions to the quadratic equation are:

b = \frac{8 + 34}{2}, b = \frac{8 - 34}{2}

x^{2} - x - 6 = 6

x, f^{- 1} (x) = x^{2} - 4

x^{2} - 18 x + 81 = 0

- 6 x^{2} + 18 x - 12 = 0

(x - 2)^{2} - 10 = 26

What are the solutions to the equation 2b^2+15=16b ?
The solutions to the equation 2b^2+15=16b are b=(8+sqrt(34))/2 ,b=(8-sqrt(34))/2
Find the zeros of 2b^2+15=16b
The zeros of 2b^2+15=16b are b=(8+sqrt(34))/2 ,b=(8-sqrt(34))/2