What are the solutions to the equation 7x^2-4=3x^2-12 ?

The solutions to the equation 7x^2-4=3x^2-12 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of 7x^2-4=3x^2-12

The zeros of 7x^2-4=3x^2-12 are x=sqrt(2)i,x=-sqrt(2)i

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7 x^{2} - 4 = 3 x^{2} - 12

x = 2 i, x = - 2 i

Solution steps

7 x^{2} - 4 = 3 x^{2} - 12

Move

4

to the right side

7 x^{2} = 3 x^{2} - 8

Move

3 x^{2}

to the left side

4 x^{2} = - 8

Divide both sides by

4

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

4.9 x^{2} - 40 x - 14 = 0

x, x^{2} + x + 4 = 0

3 x^{2} + 8 x = 2

x, 4 x^{2} - 9 y^{2} + z^{2} = 36

3 x^{2} - 4 x + 5

What are the solutions to the equation 7x^2-4=3x^2-12 ?
The solutions to the equation 7x^2-4=3x^2-12 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of 7x^2-4=3x^2-12
The zeros of 7x^2-4=3x^2-12 are x=sqrt(2)i,x=-sqrt(2)i