What are the solutions to the equation 3x^2+8x=2 ?

The solutions to the equation 3x^2+8x=2 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3

Find the zeros of 3x^2+8x=2

The zeros of 3x^2+8x=2 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3

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3 x^{2} + 8 x = 2

x = \frac{- 4 + 22}{3}, x = - \frac{4 + 22}{3}

Decimal Notation

x = 0.23013 \dots, x = - 2.89680 \dots

Solution steps

3 x^{2} + 8 x = 2

Move

2

to the left side

3 x^{2} + 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 2) = 222

x_{1, 2} = \frac{- 8 \pm 2 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 2 22}{2 \cdot 3}, x_{2} = \frac{- 8 - 2 22}{2 \cdot 3}

x = \frac{- 8 + 2 22}{2 \cdot 3} : \frac{- 4 + 22}{3}

x = \frac{- 8 - 2 22}{2 \cdot 3} : - \frac{4 + 22}{3}

The solutions to the quadratic equation are:

x = \frac{- 4 + 22}{3}, x = - \frac{4 + 22}{3}

x, 4 x^{2} - 9 y^{2} + z^{2} = 36

3 x^{2} - 4 x + 5

10 x - 5 - x^{2} = 16 x - 10 - 2 x^{2}

x, x (1 - x) y^{n} + (\frac{3}{2} - 2 x) y^{1} + 2 y = 0

x^{2} + 11 x - 522 = 0

What are the solutions to the equation 3x^2+8x=2 ?
The solutions to the equation 3x^2+8x=2 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3
Find the zeros of 3x^2+8x=2
The zeros of 3x^2+8x=2 are x=(-4+sqrt(22))/3 ,x=-(4+sqrt(22))/3