What are the solutions to the equation x^2+11x-522=0 ?

The solutions to the equation x^2+11x-522=0 are x=18,x=-29

Find the zeros of x^2+11x-522=0

The zeros of x^2+11x-522=0 are x=18,x=-29

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x^{2} + 11 x - 522 = 0

x = 18, x = - 29

Solution steps

x^{2} + 11 x - 522 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 522 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 522) = 47

x_{1, 2} = \frac{- 11 \pm 47}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 47}{2 \cdot 1}, x_{2} = \frac{- 11 - 47}{2 \cdot 1}

x = \frac{- 11 + 47}{2 \cdot 1} : 18

x = \frac{- 11 - 47}{2 \cdot 1} : - 29

The solutions to the quadratic equation are:

x = 18, x = - 29

x^{2} - x = x - 1

0 = - x^{2} + 4 x + 4

x, c y^{2} + 4 y = 2 x^{2}

P^{2} = 2.97370166 \cdot 1 0^{- 19} \cdot 142830000000 0^{3}

x^{2} - 9 x - 20 = 16

What are the solutions to the equation x^2+11x-522=0 ?
The solutions to the equation x^2+11x-522=0 are x=18,x=-29
Find the zeros of x^2+11x-522=0
The zeros of x^2+11x-522=0 are x=18,x=-29