What are the solutions to the equation 0=-x^2+4x+4 ?

The solutions to the equation 0=-x^2+4x+4 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))

Find the zeros of 0=-x^2+4x+4

The zeros of 0=-x^2+4x+4 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))

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0 = - x^{2} + 4 x + 4

x = - 2 (2 - 1), x = 2 (1 + 2)

Decimal Notation

x = - 0.82842 \dots, x = 4.82842 \dots

Solution steps

0 = - x^{2} + 4 x + 4

Switch sides

- x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 4 = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 ( - 1 )}, x_{2} = \frac{- 4 - 4 2}{2 ( - 1 )}

x = \frac{- 4 + 4 2}{2 ( - 1 )} : - 2 (2 - 1)

x = \frac{- 4 - 4 2}{2 ( - 1 )} : 2 (1 + 2)

The solutions to the quadratic equation are:

x = - 2 (2 - 1), x = 2 (1 + 2)

x, c y^{2} + 4 y = 2 x^{2}

P^{2} = 2.97370166 \cdot 1 0^{- 19} \cdot 142830000000 0^{3}

x^{2} - 9 x - 20 = 16

- t^{2} + 8 t + 115 = 0

x^{2} - 2 x - 5 = 3

What are the solutions to the equation 0=-x^2+4x+4 ?
The solutions to the equation 0=-x^2+4x+4 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))
Find the zeros of 0=-x^2+4x+4
The zeros of 0=-x^2+4x+4 are x=-2(sqrt(2)-1),x=2(1+sqrt(2))