What are the solutions to the equation -t^2+8t+115=0 ?

The solutions to the equation -t^2+8t+115=0 are t=4-sqrt(131),t=4+sqrt(131)

Find the zeros of -t^2+8t+115=0

The zeros of -t^2+8t+115=0 are t=4-sqrt(131),t=4+sqrt(131)

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- t^{2} + 8 t + 115 = 0

t = 4 - 131, t = 4 + 131

Decimal Notation

t = - 7.44552 \dots, t = 15.44552 \dots

Solution steps

- t^{2} + 8 t + 115 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 115}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 115 = 2131

t_{1, 2} = \frac{- 8 \pm 2 131}{2 ( - 1 )}

Separate the solutions

t_{1} = \frac{- 8 + 2 131}{2 ( - 1 )}, t_{2} = \frac{- 8 - 2 131}{2 ( - 1 )}

t = \frac{- 8 + 2 131}{2 ( - 1 )} : 4 - 131

t = \frac{- 8 - 2 131}{2 ( - 1 )} : 4 + 131

The solutions to the quadratic equation are:

t = 4 - 131, t = 4 + 131

x^{2} - 2 x - 5 = 3

x^{2} - 2 \frac{1}{4} = 0

x^{2} - 5.6 x + 6.4 x = 0

\frac{k ^{2}}{2} + k = - \frac{1}{2}

2 x^{2} + 8 x = 0

What are the solutions to the equation -t^2+8t+115=0 ?
The solutions to the equation -t^2+8t+115=0 are t=4-sqrt(131),t=4+sqrt(131)
Find the zeros of -t^2+8t+115=0
The zeros of -t^2+8t+115=0 are t=4-sqrt(131),t=4+sqrt(131)