What are the solutions to the equation y^2=-20y ?

The solutions to the equation y^2=-20y are y=0,y=-20

Find the zeros of y^2=-20y

The zeros of y^2=-20y are y=0,y=-20

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y^{2} = - 20 y

y = 0, y = - 20

Solution steps

y^{2} = - 20 y

Move

20 y

to the left side

y^{2} + 20 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 0 = 20

y_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 20 + 20}{2 \cdot 1}, y_{2} = \frac{- 20 - 20}{2 \cdot 1}

y = \frac{- 20 + 20}{2 \cdot 1} : 0

y = \frac{- 20 - 20}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

y = 0, y = - 20

x, 8 x^{2} + 10 x y - 3 y^{2} - 2 x + 4 y - 2 = 0

x^{2} + 6 x + \frac{279}{4} = 0

24 x^{2} - 4 x = 0

- 3 x^{2} + 7 x = - 10

(x + 6) (x + 1) = 36

What are the solutions to the equation y^2=-20y ?
The solutions to the equation y^2=-20y are y=0,y=-20
Find the zeros of y^2=-20y
The zeros of y^2=-20y are y=0,y=-20