What are the solutions to the equation -3x^2+7x=-10 ?

The solutions to the equation -3x^2+7x=-10 are x=-1,x= 10/3

Find the zeros of -3x^2+7x=-10

The zeros of -3x^2+7x=-10 are x=-1,x= 10/3

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- 3 x^{2} + 7 x = - 10

x = - 1, x = \frac{10}{3}

Decimal Notation

x = - 1, x = 3.33333 \dots

Solution steps

- 3 x^{2} + 7 x = - 10

Move

10

to the left side

- 3 x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 3 ) \cdot 10}{2 ( - 3 )}

7^{2} - 4 (- 3) \cdot 10 = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 ( - 3 )}, x_{2} = \frac{- 7 - 13}{2 ( - 3 )}

x = \frac{- 7 + 13}{2 ( - 3 )} : - 1

x = \frac{- 7 - 13}{2 ( - 3 )} : \frac{10}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{10}{3}

(x + 6) (x + 1) = 36

(b - \frac{1}{3})^{2} = \frac{4}{9}

- x^{2} - 4 x - 8 = 0

- 3 x^{2} + 80 x + 27 = 0

y^{2} - 4 y - 96 = 0

What are the solutions to the equation -3x^2+7x=-10 ?
The solutions to the equation -3x^2+7x=-10 are x=-1,x= 10/3
Find the zeros of -3x^2+7x=-10
The zeros of -3x^2+7x=-10 are x=-1,x= 10/3