What are the solutions to the equation -3x^2+80x+27=0 ?

The solutions to the equation -3x^2+80x+27=0 are x=-1/3 ,x=27

Find the zeros of -3x^2+80x+27=0

The zeros of -3x^2+80x+27=0 are x=-1/3 ,x=27

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- 3 x^{2} + 80 x + 27 = 0

x = - \frac{1}{3}, x = 27

Decimal Notation

x = - 0.33333 \dots, x = 27

Solution steps

- 3 x^{2} + 80 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 3 ) \cdot 27}{2 ( - 3 )}

8 0^{2} - 4 (- 3) \cdot 27 = 82

x_{1, 2} = \frac{- 80 \pm 82}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 80 + 82}{2 ( - 3 )}, x_{2} = \frac{- 80 - 82}{2 ( - 3 )}

x = \frac{- 80 + 82}{2 ( - 3 )} : - \frac{1}{3}

x = \frac{- 80 - 82}{2 ( - 3 )} : 27

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = 27

y^{2} - 4 y - 96 = 0

y, y^{2} = c x^{4} + 3 x

3 (x - 7)^{2} = 12

λ^{2} - λ - 12 = 0

x \cdot x = 0

What are the solutions to the equation -3x^2+80x+27=0 ?
The solutions to the equation -3x^2+80x+27=0 are x=-1/3 ,x=27
Find the zeros of -3x^2+80x+27=0
The zeros of -3x^2+80x+27=0 are x=-1/3 ,x=27