What are the solutions to the equation 1t^2-11t-150=0 ?

The solutions to the equation 1t^2-11t-150=0 are t=(11+sqrt(721))/2 ,t=(11-sqrt(721))/2

Find the zeros of 1t^2-11t-150=0

The zeros of 1t^2-11t-150=0 are t=(11+sqrt(721))/2 ,t=(11-sqrt(721))/2

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1 t^{2} - 11 t - 150 = 0

t = \frac{11 + 721}{2}, t = \frac{11 - 721}{2}

Decimal Notation

t = 18.92572 \dots, t = - 7.92572 \dots

Solution steps

1 \cdot t^{2} - 11 t - 150 = 0

Refine

t^{2} - 11 t - 150 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 150 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 150) = 721

t_{1, 2} = \frac{- ( - 11 ) \pm 721}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 11 ) + 721}{2 \cdot 1}, t_{2} = \frac{- ( - 11 ) - 721}{2 \cdot 1}

t = \frac{- ( - 11 ) + 721}{2 \cdot 1} : \frac{11 + 721}{2}

t = \frac{- ( - 11 ) - 721}{2 \cdot 1} : \frac{11 - 721}{2}

The solutions to the quadratic equation are:

t = \frac{11 + 721}{2}, t = \frac{11 - 721}{2}

\frac{x ^{2}}{3} = 0

- 3 (x + 1)^{2} - 2 = 13

m, A = 3 (m + 3)^{2} - 4 (m - 3)^{2} - 42 m + 9

0 = 12 x^{2} - 18 x + 6

2 4^{2} = x^{2} + x^{2}

What are the solutions to the equation 1t^2-11t-150=0 ?
The solutions to the equation 1t^2-11t-150=0 are t=(11+sqrt(721))/2 ,t=(11-sqrt(721))/2
Find the zeros of 1t^2-11t-150=0
The zeros of 1t^2-11t-150=0 are t=(11+sqrt(721))/2 ,t=(11-sqrt(721))/2